JEE Main 2022 BTech, BE Paper Marking Scheme
Each topic of JEE Main 2022 has two sections where MCQ questions (MCQs) are asked in Section A and Answers in Section B in numerical form. In part B, students have to answer 5 out of 10 questions. There will be a negative score for both Section A and Section B and 1 point will be deducted for each incorrect answer.
Tie Break Policy: After tie in JEE Main 2022 BE, BTech paper, such tie will be resolved
1. In order to resolve the tie, first the candidate has the highest score in mathematics.
2. Then the score can be seen in Physics.
3. Then score in chemistry.
4Then the candidate with a smaller ratio between the number of wrong answers and the correct answers is seen in all subjects of the exam.
5. In the exam, the candidate with a smaller ratio between the number of wrong answers and the correct answers in Mathematics is given priority.
6. The candidate with a smaller ratio of wrong answers to correct answers in physics will be placed at the front of the exam.
7. The candidate with a smaller ratio of wrong answers to correct answers in chemistry gets a higher rank on the exam.
8. Priority is given to the older candidate.
9. Application number in ascending order.
JEE Main 2022 Marking Scheme BArch Paper
The BArch paper will consist of 20 MCQ questions and 5 of the 10 numerical value questions to be answered. There is a provision of negative marking for both Section A and Section B i.e. 4 points will be deducted for each correct answer and 1 point will be deducted for each incorrect answer. In addition, there are two 100-point questions about drawing.
Tie Break Policy: After two students have the same score in Paper 2A, the tie will be resolved as follows:
1. First of all, we will look at what the score is in mathematics.
2. What is the score in the aptitude test.
3. What is the score in the drawing test?
4. After that, the candidate with a smaller ratio between the number of wrong answers and the correct answers in all subjects of the exam is advanced.
5. Priority will be given to the candidate with a smaller ratio of the number of wrong answers and correct answers in Mathematics (Part I) in the exam.
6. Thereafter, the candidate with a smaller ratio between the number of wrong answers and the correct answers is presented in the aptitude test (Part II).
7. Preference is given to the older student.
8. Then based on ascending order of application number.
Tie Breaking Policy: Tie by equal points in BPlanning Paper 2 B will be resolved as follows:
1. First, the score is displayed in math.
2. Then score in the aptitude test.
3. Then score on planning questions.
4. The candidate with a smaller ratio of wrong answers to correct answers in all subjects in the exam will be given a higher rank.
5. The candidate with a smaller ratio between the number of wrong answers and the correct answers in Mathematics (Part I) will be placed at the front of the exam.
6. In the aptitude test (Part II), the candidate whose ratio of wrong answers to correct answers is smaller will be awarded the maximum rank.
7. With a smaller ratio of wrong answers to correct answers in Scheduled Questions (Part III), the candidate’s score will be seen in the exam.
8. Priority is given to the older candidate.
9. Application number in ascending order.
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